Kirchhoff’s loop rule state that the algebraic sum of all the voltages in a loop will certainly be zero. Or,

Solution:

a)

Given resistances are: 1 Ω,1 Ω,0.1Ω

Applying Loop preeminence, we can compose,

Or,

And i1 will certainly be,

In the following number,

Let i be the existing that passes via the middle branch and therefore i2-i will certainly pass via the top branch, as displayed in figure.

By applying loop ascendancy in AFEDA, we have the right to compose as,

Or,

Similarly, using the loop dominion in ADCBA, we deserve to write as,

Or,

Replacing ‘i’ in eqn.1 utilizing eqn.2, we acquire,

Or,

Or,

Now i1/i2 is,

b)

Given resistances are: 1 Ω,1 Ω,1Ω

Applying Loop dominance, we deserve to compose,

Or,

And i1 will certainly be,

In the following number,

Let i be the existing that passes with the middle branch and also thus i2-i will certainly pass with the top branch, as presented in figure.

By applying loop ascendancy in AFEDA, we have the right to write as,

Or,

Similarly, applying the loop rule in ADCBA, we can create as,

Or,

Replacing ‘i’ in eqn.1 using eqn.2, we acquire,

Or,

Or,

Now i1/i2 is,

c)

Given resistances are: 1 Ω,1 Ω,10Ω

Applying Loop rule, we can write,

Or,

And i1 will certainly be,

In the next number,

Let i be the existing that passes with the middle branch and also therefore i2-i will pass through the upper branch, as displayed in number.