Kirchhoff’s loop rule state that the algebraic sum of all the voltages in a loop will certainly be zero. Or,

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Solution:

a)

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Given resistances are: 1 Ω,1 Ω,0.1Ω

Applying Loop preeminence, we can compose,

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Or,

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And i1 will certainly be,

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In the following number,

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Let i be the existing that passes via the middle branch and therefore i2-i will certainly pass via the top branch, as displayed in figure.

By applying loop ascendancy in AFEDA, we have the right to compose as,

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Or,

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Similarly, using the loop dominion in ADCBA, we deserve to write as,

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Or,

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Replacing ‘i’ in eqn.1 utilizing eqn.2, we acquire,

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Or,

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Or,

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Now i1/i2 is,

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b)

*

Given resistances are: 1 Ω,1 Ω,1Ω

Applying Loop dominance, we deserve to compose,

*

Or,

*

And i1 will certainly be,

*

In the following number,

*

Let i be the existing that passes with the middle branch and also thus i2-i will certainly pass with the top branch, as presented in figure.

By applying loop ascendancy in AFEDA, we have the right to write as,

*

Or,

*

Similarly, applying the loop rule in ADCBA, we can create as,

*

Or,

*

Replacing ‘i’ in eqn.1 using eqn.2, we acquire,

*

Or,

*

Or,

*

Now i1/i2 is,

*

c)

*

Given resistances are: 1 Ω,1 Ω,10Ω

Applying Loop rule, we can write,

*

Or,

*

And i1 will certainly be,

*

In the next number,

*

Let i be the existing that passes with the middle branch and also therefore i2-i will pass through the upper branch, as displayed in number.