With a elevation of 63 in, Johnson was the shortest president of a specific club in the previous century. The club presidents of the previous century have a suppose elevation of 66.5 in and a conventional deviation of 1.3 in.

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a. What is the positive difference in between Johnson’s height and themean? b. How many type of standard deviations is that? c. Convert Johnson’s elevation to a z score. d. If we think about “usual" heights to be those that transform to z scores in between minus−2 and 2, is Johnson’s height usual or unusual?

Hello,a. The distinction in between Johnson"s elevation and also the expect is 63 - 66.5 = -3.5. Since the question desires the "positive difference", we"ll say 3.5.b. To find the variety of standard deviations, we deserve to take the difference from component a and divide by the typical deviation. In this situation, that would certainly be 3.5/1.3 = 2.69. Johnson is 2.69 traditional deviations below the mean.c. Any z-score deserve to be uncovered via the adhering to formula: z = (X - M)/SD, wbelow X is a person"s score, M is the expect, and also SD is the typical deviation. In this situation we have z = (63 - 66.5)/1.3 = -2.69.d. If we consider z-scores between - 2 and 2 to be usual, then Johnson"s score would certainly be inexplicable bereason he is exterior of that selection.
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