The typical formation reaction is the synthesis of 1 mole of a substance from its elements in their a lot of stables forms under typical conditions. The well balanced chemical equation is:

Na(s) + C(s, graphite) + 1/2 H₂(g) + 3/2 O₂(g) → NaHCO₃(s)

What mass of HF should react to develop 345 kJ of energy? Assume excess Sio2 sio2(s) + 4 HF(g) ? SiF4(g) + 2H20(,) 4Hxn--184 kJ The mass of HF reacted is 150 g.

You are watching: Standard formation reaction of solid sodium hydrogen carbonate


We are given:

Amount of energy released = -345 kJ

For the provided chemical reaction:


By Stoichiomeattempt of the reaction:

184 kJ of power is released once 4 moles of hydrofluoric gas is reacted.

So, 345 kJ kJ of energy will certainly be released as soon as =

of hydrofluoric gas is reacted.

Now, to calculate the mass of HF, we use the equation:


Molar mass of HF = 20 g/mol

Moles of HF = 7.5 moles

Putting worths in above equation, we get:


Hence, the mass of HF reacted is 150 g.

6 0
5 months ago

How long will it take for a 750 mg sample of radium with a half life of 15 days to degeneration to precisely 68mg?
weqwewe <10>

52 da

Step-by-step explanation:

Whenever a question asks you, "How lengthy to reach a specific concentration?" or somepoint comparable, you need to usage the appropriate incorporated price legislation expression.

The integrated price regulation for a first-order reactivity is

ln(/ ) = kt


₀ = 750 mg

= 68 mg

t_ ½ = 15 da

Tip 1. Calculate the value of the rate consistent.

t_½ = ln2/k Multiply each side by k

kt_½ = ln2 Divide each side by t_½

k = ln2/t_½

= ln2/15

= 0.0462 da⁻¹

Step 2. Calculate the time

ln(750/68) = 0.0462t

ln11.0 = 0.0462t

2.40 = 0.0462t Divide each side by 0.0462

t = 52 da

8 0
9 months ago

Complexes containing metals through d10 electron configurations are frequently colorless because:
Lana71 <14>



4 0
8 months ago

1. Patient is admitted with neck injury which has actually caused a loss of function in their thyroid.
Vladimir <108>

A. (i think)


3 0
9 months ago

25cm3 of gas at 1 atm has actually a temperature of 20 level celsis .

See more:
Why Is One Arm Fatter Than The Other, Your Questions Answered

Andreas93 <3>

1.28 atm


To solve this difficulty, you should use the gas legislations, more particularly the Incorporated Gas Law. It is P1V1/T1 = P2V2/T2. Ssuggest plug your worths in. But be careful! Make certain you transform your 20 level C and also 28 deg C to Kelvin, as that it the just temperature range the Gas Laws work with. Upon plugging in your worths, you gain around 1.28 atm.

6 0
4 months ago
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