We can use the ideal gas legislation to discover moles of NH3, and also then convert that to grams of NH3. We will assume that we have actually 1 liter of NH3.
You are watching: What is the density of nh3 at 800 torr and 25 c
PV = nRT
resolving for moles (n), we have actually n = PV/RT
n = moles = ?
P = push = 800 torr x 1 atm/760 torr = 1.053 atm
V = volume in liters = 1 liter
R = gas continuous = 0.0821 Latm/Kmol
T = temperature in Kelvin = 67C + 273 = 340K
n = PV/RT = (1.053)(1)/(0.0821)(340)
n = 0.0377 moles NH3
mass NH3 = 0.0377 moles x 17 g/mol = 0.641 g
Due to the fact that this is in 1 liter, the thickness = 0.641 g/liter
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