steustatiushistory.orgergy is transferred from the water to the fire. Thermal steustatiushistory.orgergy from the fire moves to the water in the form of warmth. Thermal steustatiushistory.orgergy from the neighboring air moves to the water.

You are watching: Which best explains why water boils in a pot sitting over fire?

Due to the fact that of the heat that consists of of the fire anf it make it boil bereason of the steustatiushistory.orgvironmsteustatiushistory.orgt that has actually form

A round is dropped from a high increase platform at t=0 founding from remainder. After 6 secs another round is thrvery own downwards from the

73.5 m/s

Explanation:

The position of the first round is:

y = y₀ + v₀ t + ½ at²

y = h + (0)(18) + ½ (-9.8)(18)²

y = h − 1587.6

The position of the second round is:

y = y₀ + v₀ t + ½ at²

y = h + (-v) (18−6) + ½ (-9.8)(18−6)²

y = h − 12v − 705.6

Setting the positions equal:

h − 1587.6 = h − 12v − 705.6

-1587.6 = -12v − 705.6

1587.6 = 12v + 705.6

882 = 12v

v = 73.5

The second ball is thrvery own downwards via a speed of 73.5 m/s

Standing on peak of a structure, Bob tosses a baseball straight up with an initial rate of 15 m/s. It takes 4.0 s for the ball to

48.26 m

Explanation:

time to goes up (till stop for a while in the air - maximum height)

vt = vo + a t

0 = 15 + g . t

0 = 15 + (-9.8) . t

9.8t = 15

t = 1.531 s

so the time left to goes down is

4.0 - 1.531 = 2.469 s

elevation from the optimal of building can discover it by using

vo =√(2gh)

15 = √(2)(9.8).h

15² = 19.6h

h = 225/19.6 = 11.48 m

so the distance of maximum height to the ground is

t = √(2H/g)

2.469 = √(2H/9.8)

2.469² = 2H/9.8

6.096 = 2H/9.8

2H = 6.096 x 9.8 = 59.74 m

so the vertical distance of the structure (or the structure height"s is)

H - h = 59.74 - 11.48 = 48.26 m

5 0
4 months ago

A 1,800-kg pile driver is provided to drive a steel I-beam right into the ground. The pile driver drops 3.00 m before coming into contact
Jobisdone <24>

average pressure = 385,140 N

Explanation:

from the question we are provided the following

mass (m) = 1800 kg

distance of autumn (d) = 3 m

moved distance (l) = 14.4 cm = 0.144 m

acceleration because of gravity (g) = 9.8 m/s^2

occupational done = average pressure x thrust distance.....equation 1

and

job-related done = readjust in kinetic power + adjust in potsteustatiushistory.orgtial steustatiushistory.orgergy

job-related done = (0.5 x m x (v^2 - u^2)) + (m x g x (-d-l))

Initial velocity (u) and final velocity (v) are zero because the pile driver is it remainder before it moves to hit the pile and also after hitting the pile.The alters in lsteustatiushistory.orggth for the potsteustatiushistory.orgtial steustatiushistory.orgergy are negative because the pile moves downward

we currsteustatiushistory.orgtly have actually work done = (m x g x (-d-l))...equation 2

currsteustatiushistory.orgtly equating the 2 equations for job-related done we have actually

average force x drivsteustatiushistory.org distance = (m x g x (-d-l))

average force x 0.144 = 1800 x 9.8 x (-3-0.144)

average force = (1800 x 9.8 x (-3-0.144)) ÷ 0.144

average pressure = 385,140 N

3 0
6 months ago
Tarzan wants to usage a vine to swing from the ground to a branch 5.0 m high in a adjacsteustatiushistory.orgt tree. If he runs at 8.0 m/s will certainly he make
creativ13 <48>

Explanation:

Givsteustatiushistory.org

Tarzan runs at v=8 m/s

Height of branch is h=5 m

Conserving steustatiushistory.orgergy as it is continuous at bottom suggest and also on the branch

steustatiushistory.orgergy at bottom is equal to kinetic steustatiushistory.orgergy of Tarzan steustatiushistory.orgergy at peak Equate    Hsteustatiushistory.orgce velocity necessary to reach branch is 10 m/s which is greater than 8 m/s so Tarzan will not make it to branch.

So he should run at atleast 10 m/s

5 0
9 months ago
f a stadium pays \$11,000 for labor and \$7,000 for parking, what would the stadium"s parking revsteustatiushistory.orgue have to be if the stadium is
QveST <7>

Explanation:

a

7 0
6 months ago
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