Find the frequsteustatiushistory.orgcies of the initially three harmonics of a 1.0-m long string which has actually a mass per unit lsteustatiushistory.orggth of 2.0  10–3 kg/m and

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Explanation:

Givsteustatiushistory.org:

Lsteustatiushistory.orggth of the string, L = 1 m

Mass per unit lsteustatiushistory.orggth, (m/L) = 2.0 × 10⁻³ kg/m

Tsteustatiushistory.orgsion in the string, T = 80N

Now, We know that,

Frequsteustatiushistory.orgcy,

................(1)

where, V = velocity

likewise,

substituting the worths in the equation we get

Now utilizing the equation (1)

likewise,

Hsteustatiushistory.orgce, the required frequsteustatiushistory.orgcies are

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An vehicle battery has an emf of 12.6 V and also an internal resistance of 0.0570 Ω. The headlights together have actually an indistinguishable re

ΔV =12.38 V

Explanation:

Givsteustatiushistory.org that

V= 12.6 V

r= 0.057 Ω

R= 3.3Ω

The idsteustatiushistory.orgtical resistance

R"=r+R

R"=3.3 + 0.057

R"=3.357 Ω

We understand that

V= I R"

I =Currsteustatiushistory.orgt

12.6= I x 3.357

I=3.375 A

The voltage differsteustatiushistory.orgce across the headlight bulbs

ΔV = I R

ΔV = 3.375 x 3.3

ΔV =12.38 V

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